x^2+4x+120=0

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Solution for x^2+4x+120=0 equation:


Simplifying
x2 + 4x + 120 = 0

Reorder the terms:
120 + 4x + x2 = 0

Solving
120 + 4x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-120' to each side of the equation.
120 + 4x + -120 + x2 = 0 + -120

Reorder the terms:
120 + -120 + 4x + x2 = 0 + -120

Combine like terms: 120 + -120 = 0
0 + 4x + x2 = 0 + -120
4x + x2 = 0 + -120

Combine like terms: 0 + -120 = -120
4x + x2 = -120

The x term is 4x.  Take half its coefficient (2).
Square it (4) and add it to both sides.

Add '4' to each side of the equation.
4x + 4 + x2 = -120 + 4

Reorder the terms:
4 + 4x + x2 = -120 + 4

Combine like terms: -120 + 4 = -116
4 + 4x + x2 = -116

Factor a perfect square on the left side:
(x + 2)(x + 2) = -116

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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